[摘要]：求∫1/(2+sinx)dx的不定积分_作业帮let tg(x/2)=two can got sinx=2t/(1+t^2) and x=2arctgt.so,dx=[2/(1+t^2)]dtthen ∫1/(2+sinx)dx =∫[1/(1+t+t^2)...
